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Proof step 6 from proof BFS-correct-if-reachable (previous step)

S0 = ∅, S = ∅, ¬ done0, 0 = n - n0, INV(∅, ∅, S1, n0, source), INVR(∅, ∅, S1, n0, n, source, dest) ⊦ ⟪while S0 ≠ ∅ ∧ ¬ done0 do { choose v with v ∈ S0 in if v = dest then done0 := true else { S0 := S0 -- v ; ADD(succ(v); S1, S) } ; if S0 = ∅ then S0 := S, S := ∅, n0 := n0 + 1 }⟫ ⟪norfail0 := (done0 ⊃ some(n0); fail)⟫ norfail0 = some(n)

User applied rule while exit right

And obtained the following new goals

Proof step 5:
S0 = ∅, S = ∅, ¬ done0, 0 = n - n0, INV(∅, ∅, S1, n0, source), INVR(∅, ∅, S1, n0, n, source, dest) ⊦ ⟪norfail0 := (done0 ⊃ some(n0); fail)⟫ norfail0 = some(n)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]