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Proof step 10 from proof BFS-returns-fail-implies-not-reachable (previous step)

〈ADD(succ(v); S1, S)〉 (S1 = s ∧ S = s0), ⟪ADD(succ(v); S1, S)⟫ INV(∅, S, S1, n0, source), v ≠ dest, INV(∅ ++ v, S, S1, n0, source), INV(∅, s0, s, n0, source), reach(source, dest, n), ∀ n. ¬ reach(source, dest, n) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 7, [QUANTTERMLIST : (n)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (n)]]