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Proof step 35 from proof BFS-returns-fail-implies-not-reachable (previous step)

¬ (S0 ≠ ∅ ∧ ¬ done0), ∀ n. ¬ reach(source, dest, n), done0 → dest ∈ S0, INV(S0, S, S1, n0, source) ⊦ [norfail0 := (done0 ⊃ some(n0); fail)] norfail0 = fail

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 34:
¬ (S0 ≠ ∅ ∧ ¬ done0), ∀ n. ¬ reach(source, dest, n), done0 → dest ∈ S0, INV(S0, S, S1, n0, source), ((done0 ⊃ some(n0); fail)) ≠ fail ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]