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Proof step 4 from proof BFS-returns-fail-implies-not-reachable (previous step)

INV(S0, S, S1, n0, source), dest ∈ S0, reach(source, dest, n), ∀ n. ¬ reach(source, dest, n) ⊦ # S0 = 0, S0 = ∅

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (n)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (n)]]