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Proof step 17 from proof INV-step (previous step)

reachS(source, C, n), v ∈ C, b ∈ succ(v), reach<(source, b, n + 1) ⊦ # succ(v) = 0, N ∪ (succ(v) \ V) = ∅, C = ∅, # C = 0, # (N ∪ (succ(v) \ V)) = 0, succ(v) = ∅, b ∈ N, b ∈ V, ∃ b1. ¬ ((∃ c. reach(source, c, n) ∧ b1 ∈ succ(c)) ∧ ¬ reach<(source, b1, n + 1) → b1 ∈ N ∨ (∃ a. a ∈ C ∧ b1 ∈ succ(a) ∧ ¬ b1 ∈ V)), ∃ b1. ¬ (b1 ∈ V ↔ reach<(source, b1, n + 1) ∨ (∃ a. b1 ∈ succ(a) ∧ reach(source, a, n) ∧ ¬ reach<(source, a, n) ∧ ¬ a ∈ C))

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 10, [QUANTTERMLIST : (b)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m])], [EXTRATERMS : (b)]]