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Proof step 28 from proof INVR-step (previous step)

c1 ∈ succ(v), reach(c1, dest, m), dest ∈ succ(c0), reach(source, c0, m + n), reachS(source, C, n), reachS(source, N, n + 1), dest ∈ succ(c), reach(v, c, m), v ∈ C, c1 ∈ N, ∀ a. a = v ∨ ¬ a ∈ C ∨ (∀ c1. ¬ reach(a, c1, m) ∨ ¬ dest ∈ succ(c1)) ∨ reach<(a, dest, m + 1), ∀ b. ¬ b ∈ N ∪ (succ(v) \ V) ∨ ¬ reach(b, dest, m) ∨ reach<(b, dest, m) ⊦ N = ∅, # succ(v) = 0, succ(c0) = ∅, succ(c) = ∅, # C = 0, v = dest, C = ∅, # succ(c0) = 0, # succ(c) = 0, succ(v) = ∅, # N = 0, reach<(source, dest, (m + 1) + n), reach<(v, dest, m + 1), ∃ b0. ¬ (b0 ∈ V ↔ reach<(source, b0, n + 1) ∨ (∃ a0. b0 ∈ succ(a0) ∧ reach(source, a0, n) ∧ ¬ reach<(source, a0, n) ∧ ¬ a0 ∈ C)), ∃ b0. ¬ ((∃ c. reach(source, c, n) ∧ b0 ∈ succ(c)) ∧ ¬ reach<(source, b0, n + 1) → b0 ∈ N ∨ (∃ a. a ∈ C ∧ b0 ∈ succ(a) ∧ ¬ b0 ∈ V))

User applied rule all left

And obtained the following new goals

Proof step 27:
c1 ∈ succ(v), reach(c1, dest, m), dest ∈ succ(c0), reach(source, c0, m + n), reachS(source, C, n), reachS(source, N, n + 1), dest ∈ succ(c), reach(v, c, m), v ∈ C, c1 ∈ N, ∀ a. a = v ∨ ¬ a ∈ C ∨ (∀ c1. ¬ reach(a, c1, m) ∨ ¬ dest ∈ succ(c1)) ∨ reach<(a, dest, m + 1), ¬ c1 ∈ N ∪ (succ(v) \ V) ∨ ¬ reach(c1, dest, m) ∨ reach<(c1, dest, m), ∀ b. ¬ b ∈ N ∪ (succ(v) \ V) ∨ ¬ reach(b, dest, m) ∨ reach<(b, dest, m) ⊦ N = ∅, # succ(v) = 0, succ(c0) = ∅, succ(c) = ∅, # C = 0, v = dest, C = ∅, # succ(c0) = 0, # succ(c) = 0, succ(v) = ∅, # N = 0, reach<(source, dest, (m + 1) + n), reach<(v, dest, m + 1), ∃ b0. ¬ (b0 ∈ V ↔ reach<(source, b0, n + 1) ∨ (∃ a0. b0 ∈ succ(a0) ∧ reach(source, a0, n) ∧ ¬ reach<(source, a0, n) ∧ ¬ a0 ∈ C)), ∃ b0. ¬ ((∃ c. reach(source, c, n) ∧ b0 ∈ succ(c)) ∧ ¬ reach<(source, b0, n + 1) → b0 ∈ N ∨ (∃ a. a ∈ C ∧ b0 ∈ succ(a) ∧ ¬ b0 ∈ V))

Rule argument

[EXRARG : pos: left 12, [extquanttermlist: (c1)abort:F, discard:F, computed:F]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (c1)]]