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Proof step 62 from proof INVR-step (previous step)

dest ∈ succ(c), reach(source, c, m + n), v ∈ C, b ∈ N, reach(b, dest, m), reachS(source, N, n + 1), reachS(source, C, n), ∀ a. a = v ∨ ¬ a ∈ C ∨ (∀ c0. ¬ reach(a, c0, m) ∨ ¬ dest ∈ succ(c0)) ∨ reach<(a, dest, m + 1), ∀ b. ¬ b ∈ N ∪ (succ(v) \ V) ∨ ¬ reach(b, dest, m) ∨ reach<(b, dest, m) ⊦ succ(c) = ∅, # N = 0, C = ∅, v = dest, # C = 0, N = ∅, # succ(c) = 0, reach<(b, dest, m), reach<(source, dest, (m + 1) + n), ∃ b0. ¬ ((∃ c. reach(source, c, n) ∧ b0 ∈ succ(c)) ∧ ¬ reach<(source, b0, n + 1) → b0 ∈ N ∨ (∃ a. a ∈ C ∧ b0 ∈ succ(a) ∧ ¬ b0 ∈ V)), ∃ b0. ¬ (b0 ∈ V ↔ reach<(source, b0, n + 1) ∨ (∃ a0. b0 ∈ succ(a0) ∧ reach(source, a0, n) ∧ ¬ reach<(source, a0, n) ∧ ¬ a0 ∈ C))

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 9, [QUANTTERMLIST : (b)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ a ∈ s1 ∪ s2 ↔ a ∈ s1 ∨ a ∈ s2], [CSIMPSEQ : ⊦ (s ∪ s0) ∪ s1 = s ∪ s0 ∪ s1], [CSIMPSEQ : ⊦ s ∪ s0 = s0 ∪ s])], [EXTRATERMS : (b)]]