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Proof step 30 from proof path-equiv-reach (previous step)

(a ' + y0) .last = y1 .last, # y1 = # y0, reach(a, y1 .last, # y0), path(a ' + y1 + a0 '), path(a ' + y0) ⊦ ∃ c. reach(a, c, # y0) ∧ a0 ∈ succ(c)

User applied rule exists right

And obtained the following new goals

Proof step 29:
(a ' + y0) .last = y1 .last, # y1 = # y0, reach(a, y1 .last, # y0), path(a ' + y1 + a0 '), path(a ' + y0) ⊦ reach(a, y1 .last, # y0) ∧ a0 ∈ succ(y1 .last)

Rule argument

[EXRARG : pos: right 1, [extquanttermlist: (y1 .last)abort:F, discard:T, computed:T]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (y1 .last)]]