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Proof step 44 from proof path-equiv-reach (previous step)

(a0 ' + y0) .last ≠ y0 .last, path(a0 ' + y0 + a ') ⊦ reach(a0, y0 .last, # y0), ∃ c. reach(a0, c, # y0) ∧ a ∈ succ(c)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 43:
path(a0 ' + y0 + a ') ⊦ (a0 ' + y0) .last = y0 .last, reach(a0, y0 .last, # y0), ∃ c. reach(a0, c, # y0) ∧ a ∈ succ(c)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]