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Proof step 6 from proof reach-rec-rev (previous step)

b ∈ succ(c), c ∈ succ(c0), reach(a, c0, n0), reach(a, b, 2 + n0) ⊦ ∃ c0. reach(a, c0, n0) ∧ c ∈ succ(c0), succ(c) = ∅, succ(c0) = ∅, # succ(c) = 0, # succ(c0) = 0, ∃ c. c ∈ succ(a) ∧ (∃ c0. reach(c, c0, n0) ∧ b ∈ succ(c0))

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

[EXRARG : pos: right 1, [QUANTTERMLIST : (c0)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (c0)]]