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Proof step 4 from proof reach-trans (previous step)

c ∈ succ(c0), reach(b, c0, m0), reach(a, b, n), reach(a, b, n) ∧ reach(b, c0, m0) → reach(a, c0, m0 + n) ⊦ succ(c0) = ∅, # succ(c0) = 0, ∃ c0. reach(a, c0, m0 + n) ∧ c ∈ succ(c0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
c ∈ succ(c0), reach(b, c0, m0), reach(a, b, n), reach(a, c0, m0 + n) ⊦ succ(c0) = ∅, # succ(c0) = 0, ∃ c0. reach(a, c0, m0 + n) ∧ c ∈ succ(c0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]