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Proof step 9 from proof reachless-edge (previous step)

reach<(source, a, n0), b ∈ succ(a) ⊦ succ(a) = ∅, # succ(a) = 0, ∃ m. m < n0 + 1 ∧ reach(source, b, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
reach<(source, a, n0), b ∈ succ(a) ⊦ succ(a) = ∅, # succ(a) = 0, ∃ m. ¬ n0 < m ∧ reach(source, b, m)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m])]]