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Proof step 4 from proof reachless-next (previous step)

∃ m. m < n + 1 ∧ reach(a, b, m) ⊦ ∃ m. m < n + 2 ∧ reach(a, b, m)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
reach(a, b, m), m ≤ n ⊦ ∃ m. m < n + 2 ∧ reach(a, b, m)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m < n + 1 ↔ ¬ n < m])]]