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Proof step 4 from proof at-first-mod (previous step)

i→n(buf .first) < i→n(buf .size) → i→n(buf .first) % i→n(buf .size) = i→n(buf .first), inv(buf) ⊦ i→n(buf .first) % i→n(buf .size) = i→n(buf .first)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
inv(buf), abs(buf .size) ≤ abs(buf .first) ⊦ i→n(buf .first) % i→n(buf .size) = i→n(buf .first)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ i→n(i) < i→n(j) ↔ abs(i) < abs(j)])]]