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Proof step 6 from proof at-first-mod (conclusion)

⊦ inv(buf) → i→n(buf .first) % i→n(buf .size) = i→n(buf .first)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
inv(buf) ⊦ i→n(buf .first) % i→n(buf .size) = i→n(buf .first)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]