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Proof step 8 from proof mod-twice (previous step)

⊦ m = 0, (n0 % m + n1) % m = (n0 + n1) % m

User applied rule induction

And obtained the following new goals

Proof step 7:
true, ∀ n, m, n1. n < n0 → (true → m = 0 ∨ (n % m + n1) % m = (n + n1) % m) ⊦ m = 0 ∨ (n0 % m + n1) % m = (n0 + n1) % m

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, n0, [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (n0)]]