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Proof step 12 from proof test (previous step)

⊦ ⟪buf0 := mk(mkarray(2)[0, a][1, b][0, c], 2, 0, 1)⟫ ⟪pop#(; buf0, b)⟫ ⟪assert#(b = c)⟫ true

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 11:
buf = mk(mkarray(2)[0, a][1, b][0, c], 2, 0, 1) ⊦ ⟪pop#(; buf, b)⟫ ⟪assert#(b = c)⟫ true

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]