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Proof step 17 from proof test (previous step)

buf = mk(mkarray(2)[0, a][1, b][0, c], 2, 1, 2), a1 = a0 ∧ ar0 = buf .data ∧ i0 = buf .first ⊦ ⟪assert#(ar0[i→n(i0)] = b)⟫ ⟪a1 := ar0[i→n(i0)] ; buf0 := buf .first:= ((buf .first + 1) % buf .size) .len:= ((buf .first:= ((buf .first + 1) % buf .size)) .len - 1) ; pop#(; buf0, a1) ; assert#(a1 = c)⟫ true

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
⊦ ⟪assert#(true)⟫ ⟪a1 := b ; buf0 := mk(mkarray(2)[0, a][1, b][0, c], 2, 0, 1) ; pop#(; buf0, a1) ; assert#(a1 = c)⟫ true

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .len:= i4 = mk(ar, i, i0, i4)], [CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .len = i1], [CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .first:= i3 = mk(ar, i, i3, i1)], [CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .size = i], [CSIMPSEQ : m < # ar ⊦ (ar[m, a][m]) = a], [CSIMPSEQ : ⊦ # (ar[n, a]) = # ar], [CSIMPSEQ : ⊦ # mkarray(n) = n], [CSIMPSEQ : ⊦ (ar[0, a][1]) = ar[1]], [CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .first = i0], [CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .data = ar])]]