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Proof step 21 from proof test (previous step)

buf = mk(mkarray(2)[0, a][1, b][0, c], 2, 1, 2), a1 = a0 ∧ ar0 = buf .data ∧ i0 = buf .first ⊦ ⟪if 0 ≤ i0 ∧ i0 < n→i(# ar0) then a1 := ar0[i→n(i0)] else abort⟫ ⟪buf0 := buf .first:= ((buf .first + 1) % buf .size) ; buf0 := buf0 .len:= (buf0 .len - 1)⟫ ⟪assert#(a1 = b) ; pop#(; buf0, a1) ; assert#(a1 = c)⟫ true

Heuristic symbolic execution applied rule if positive right

And obtained the following new goals

Proof step 20:
buf = mk(mkarray(2)[0, a][1, b][0, c], 2, 1, 2), a1 = a0 ∧ ar0 = buf .data ∧ i0 = buf .first ⊦ ⟪a1 := ar0[i→n(i0)]⟫ ⟪buf0 := buf .first:= ((buf .first + 1) % buf .size) ; buf0 := buf0 .len:= (buf0 .len - 1)⟫ ⟪assert#(a1 = b) ; pop#(; buf0, a1) ; assert#(a1 = c)⟫ true

Rule argument

[fmapos-arg: pos: right 1]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .first = i0], [CSIMPSEQ : ⊦ mk(ar, i, i0, i1) .data = ar], [CSIMPSEQ : ⊦ # (ar[n, a]) = # ar], [CSIMPSEQ : ⊦ # mkarray(n) = n])]]