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Proof step 36 from proof test (previous step)

⊦ ⟪buf0 := mk(mkarray(2)[0, a][1, b], 2, 1, 1)⟫ ⟪push#(c; buf0)⟫ ⟪a2 := a ; pop#(; buf0, a2) ; assert#(a2 = b) ; pop#(; buf0, a2) ; assert#(a2 = c)⟫ true

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 35:
buf = mk(mkarray(2)[0, a][1, b], 2, 1, 1) ⊦ ⟪push#(c; buf)⟫ ⟪a2 := a ; pop#(; buf, a2) ; assert#(a2 = b) ; pop#(; buf, a2) ; assert#(a2 = c)⟫ true

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]