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Proof step 68 from proof test (previous step)

⊦ ⟪buf := mk(mkarray(i→n(2)), 2, 0, 0)⟫ ⟪push#(a; buf) ; push#(b; buf) ; pop#(; buf, a0) ; assert#(a0 = a) ; push#(c; buf) ; pop#(; buf, a0) ; assert#(a0 = b) ; pop#(; buf, a0) ; assert#(a0 = c)⟫ true

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 67:
buf0 = mk(mkarray(i→n(2)), 2, 0, 0) ⊦ ⟪push#(a; buf0)⟫ ⟪push#(b; buf0) ; pop#(; buf0, a0) ; assert#(a0 = a) ; push#(c; buf0) ; pop#(; buf0, a0) ; assert#(a0 = b) ; pop#(; buf0, a0) ; assert#(a0 = c)⟫ true

Rule argument

[emptyarg]

Additional information

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