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Proof step 70 from proof test (previous step)

⊦ ∀ a1. ⟪create#(2; buf0) ; push#(a; buf0) ; push#(b; buf0) ; pop#(; buf0, a1) ; assert#(a1 = a) ; push#(c; buf0) ; pop#(; buf0, a1) ; assert#(a1 = b) ; pop#(; buf0, a1) ; assert#(a1 = c)⟫ true

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 69:
⊦ ⟪create#(2; buf0)⟫ ⟪push#(a; buf0) ; push#(b; buf0) ; pop#(; buf0, a0) ; assert#(a0 = a) ; push#(c; buf0) ; pop#(; buf0, a0) ; assert#(a0 = b) ; pop#(; buf0, a0) ; assert#(a0 = c)⟫ true

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]