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Proof step 35 from proof max-concat (previous step)

true, ∀ x0, y0. # x0 + # y0 < # x + # y → (true → x0 = [] ∨ y0 = [] ∨ max(x0 + y0) = max(max(x0), max(y0))) ⊦ x = [] ∨ y = [] ∨ max(x + y) = max(max(x), max(y))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 34:
∀ x0, y0. # x0 + # y0 < # x + # y → (true → x0 = [] ∨ y0 = [] ∨ max(x0 + y0) = max(max(x0), max(y0))) ⊦ max(x + y) = max(max(x), max(y)), y = [], x = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]