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Proof step 10 from proof max-ge (previous step)

x = i0 + x1, max(x) < i, i ∈ x, ∀ x0, i. # x0 < # x → (i ∈ x0 ∧ max(x0) < i → false) ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
max(i0 ' + x1) < i, ∀ x0, i. # x0 < # (i0 + x1) → (i ∈ x0 ∧ max(x0) < i → false) ⊦ i ≠ i0 ∧ ¬ i ∈ x1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (x + y) + z = x + y + z], [CSIMPSEQ : ⊦ d ∈ d0 ' ↔ d = d0], [CSIMPSEQ : ⊦ d ∈ x + y ↔ ¬ ¬ (d ∈ x ∨ d ∈ y)], [CSIMPSEQ : ⊦ d + x = d ' + x])]]