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Proof step 12 from proof max-ge (previous step)

i ∈ x ∧ max(x) < i, ∀ x0, i. # x0 < # x → (i ∈ x0 ∧ max(x0) < i → false) ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
max(x) < i, i ∈ x, ∀ x0, i. # x0 < # x → (i ∈ x0 ∧ max(x0) < i → false) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]