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Proof step 5 from proof max-ge (previous step)

¬ i0 < i1, i0 < i, i1 < i, max(min(i0, i1) ' + x) < i, i ∈ x, ∀ x0, i. # x0 < # (i0 + i1 + x) → (i ∈ x0 ∧ max(x0) < i → false) ⊦ i = i1, i = i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i ∈ x, i0 < i, max(i1 ' + x) < i, i1 ≤ i0, i1 < i, ∀ x0, i. # x0 < # (i0 + i1 + x) → (i ∈ x0 ∧ max(x0) < i → false) ⊦ i = i0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ j < j0 → i < j0], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ min(i, j) = min(j, i)], [CSIMPSEQ : ⊦ min(i, min(j, j0)) = min(min(i, j), j0)], [CSIMPSEQ : ⊦ ¬ j < i → min(j, i) = i])]]