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Proof step 12 from proof max-in (previous step)

true, ∀ x0. # x0 < # x → (true → x0 = [] ∨ max(x0) ∈ x0) ⊦ x = [] ∨ max(x) ∈ x

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
∀ x0. # x0 < # x → (true → x0 = [] ∨ max(x0) ∈ x0) ⊦ x = [], max(x) ∈ x

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]