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Proof step 4 from proof min-le-max (previous step)

max(x) ∈ x → min(x) ≤ max(x), max(x) < min(x) ⊦ x = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
max(x) < min(x) ⊦ x = [], max(x) ∈ x

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])]]