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Proof step 6 from proof min-le-max (conclusion)

⊦ x ≠ [] → min(x) ≤ max(x)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
max(x) < min(x) ⊦ x = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i])]]