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Proof step 13 from proof min-le (previous step)

i ∈ x ∧ i < min(x), ∀ x0, i. # x0 < # x → (i ∈ x0 ∧ i < min(x0) → false) ⊦ false

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
i < min(x), i ∈ x, ∀ x0, i. # x0 < # x → (i ∈ x0 ∧ i < min(x0) → false) ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]