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Proof step 18 from proof harness-1 (previous step)

to3 = fail, x0 = 2 ', x1 = x0 ∧ d0 = 2, h0 = head(x1) ⊦ 〈to := some(Leaf)〉〈to3 := to ; if to3 = fail then to := fail else to := some(Node(Node(Leaf, Leaf), to3 .t))〉〈to5 := to ; if to5 = fail then to0 := fail else to0 := some(Node(Leaf, to5 .t))〉〈to1 := to0 ; if pop(x1) ≠ [] then to1 := fail〉 to1 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 17:
to3 = fail, x0 = 2 ', x1 = x0 ∧ d0 = 2, h0 = head(x1) ⊦ 〈to3 := some(Leaf)〉〈if to3 = fail then to := fail else to := some(Node(Node(Leaf, Leaf), to3 .t))〉〈to5 := to ; if to5 = fail then to0 := fail else to0 := some(Node(Leaf, to5 .t))〉〈to1 := to0 ; if pop(x1) ≠ [] then to1 := fail〉 to1 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]