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Proof step 73 from proof harness-1 (previous step)

x1 = 1 ' + 3 ' + 3 ' + 2 ', to3 = fail, x0 = x1 ∧ d0 = 1, h0 = head(x0) ⊦ 〈to := some(Leaf)〉〈to3 := to, x1 := pop(x0) ; if to3 = fail then to0 := fail else { to := fail ; build_rec#(1; x1, to) ; if to = fail then to0 := fail else to0 := some(Node(to3 .t, to .t)) }〉〈to1 := to0 ; if x1 ≠ [] then to1 := fail〉 to1 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 72:
x1 = 1 ' + 3 ' + 3 ' + 2 ', to3 = fail, x0 = x1 ∧ d0 = 1, h0 = head(x0) ⊦ 〈to3 := some(Leaf), x1 := pop(x0)〉〈if to3 = fail then to0 := fail else { to := fail ; build_rec#(1; x1, to) ; if to = fail then to0 := fail else to0 := some(Node(to3 .t, to .t)) }〉〈to1 := to0 ; if x1 ≠ [] then to1 := fail〉 to1 = some(Node(Leaf, Node(Node(Leaf, Leaf), Leaf)))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]