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Proof step 10 from proof harness-2 (previous step)

x = 2 ' + 2 ', to6 = fail, x2 = x ∧ d0 = 3, h0 = head(x2), to2 = fail ∧ x0 = x2 ⊦ 〈to1 := fail〉〈if x0 ≠ [] then to1 := fail〉 to1 = fail

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 9:
x = 2 ' + 2 ', to6 = fail, x2 = x ∧ d0 = 3, h0 = head(x2), to2 = fail ∧ x0 = x2, to = fail ⊦ 〈if x0 ≠ [] then to := fail〉 to = fail

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]