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Proof step 31 from proof harness-2 (previous step)

x0 = 3 ' + 2 ' + 2 ', to4 = fail, x2 = x0 ∧ d0 = 3, h0 = head(x2) ⊦ 〈x2 := pop(x2)〉〈to := some(Leaf)〉〈to4 := to, x0 := x2 ; if to4 = fail then to := fail else { to2 := fail ; build_rec#(3; x0, to2) ; if to2 = fail then to := fail else to := some(Node(to4 .t, to2 .t)) }〉〈to3 := to, x1 := x0 ; if to3 = fail then to := fail else { to2 := fail ; build_rec#(2; x1, to2) ; if to2 = fail then to := fail else to := some(Node(to3 .t, to2 .t)) }〉〈to4 := to ; if to4 = fail then to0 := fail else to0 := some(Node(Leaf, to4 .t))〉〈to1 := to0 ; if x1 ≠ [] then to1 := fail〉 to1 = fail

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 30:
x0 = 3 ' + 2 ' + 2 ', to4 = fail, x2 = x0 ∧ d0 = 3, h0 = head(x2) ⊦ 〈to := some(Leaf)〉〈to4 := to, x0 := pop(x2) ; if to4 = fail then to := fail else { to2 := fail ; build_rec#(3; x0, to2) ; if to2 = fail then to := fail else to := some(Node(to4 .t, to2 .t)) }〉〈to3 := to, x1 := x0 ; if to3 = fail then to := fail else { to2 := fail ; build_rec#(2; x1, to2) ; if to2 = fail then to := fail else to := some(Node(to3 .t, to2 .t)) }〉〈to4 := to ; if to4 = fail then to0 := fail else to0 := some(Node(Leaf, to4 .t))〉〈to1 := to0 ; if x1 ≠ [] then to1 := fail〉 to1 = fail

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]