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Proof step 56 from proof harness-2 (previous step)

x1 = 1 ' + 3 ' + 2 ' + 2 ', to3 = fail, x0 = x1 ∧ d0 = 1, h0 = head(x0), to2 = some(Leaf) ∧ x = pop(x0) ⊦ 〈if to2 = fail then to0 := fail else { to := fail ; build_rec#(1; x, to) ; if to = fail then to0 := fail else to0 := some(Node(to2 .t, to .t)) }〉〈to1 := to0 ; if x ≠ [] then to1 := fail〉 to1 = fail

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Proof step 55:
x1 = 1 ' + 3 ' + 2 ' + 2 ', to3 = fail, x0 = x1 ∧ d0 = 1, h0 = head(x0), to2 = some(Leaf) ∧ x = pop(x0) ⊦ 〈to := fail〉〈build_rec#(1; x, to)〉〈if to = fail then to0 := fail else to0 := some(Node(to2 .t, to .t))〉〈to1 := to0 ; if x ≠ [] then to1 := fail〉 to1 = fail

Rule argument

[fmapos-arg: pos: right 1]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ fail ≠ some(t)])]]