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Proof step 7 from proof soundness-rec (previous step)

〈build_rec#(i + 1; x2, to2)〉 (x2 = x1 ∧ to2 = some(t)), ∀ j0, i0, x, x0, to. i→n(j0 - i0) < i→n(i1) → (x = x0 ∧ x0 ≠ [] ∧ i0 ≤ j0 ∧ max(x0) ≤ j0 → 〈build_rec#(i0; x, to)〉 (to ≠ fail → x0 = depths(to .t, i0) + x)), x2 = d ' + y, to2 = fail, d ' + y = depths(t, i + 1) + x1, 0 ≠ i1, d ∈ depths(t, i + 1), max(d ' + y) ≤ i1 + i, i < d, 0 < i1, i1 + i < max(x1), max(d ' + y) < max(x1), x0 = x1 ∧ d1 = i + 1, is_empty(x0) ⊦ 〈to0 := fail〉 (to0 ≠ fail → d ' + y = depths(to0 .t, i) + x0)

Proof step 7 from proof soundness-rec (previous step)

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

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