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Proof step 30 from proof soundness (previous step)

〈build_rec#(0; x, to)〉 (x = x1 ∧ to = to1), x2 = x, x0 = x, to1 ≠ fail → x0 = depths(to1 .t, 0) + x1, to2 = to1 ∧ x3 = x1, x3 ≠ [] ⊦ 〈to2 := fail〉 (to2 ≠ fail → x2 = depths(to2 .t, 0))

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]