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Proof step 5 from proof soundness (previous step)

x = [], x2 = x ∧ d0 = 0, to = fail ∧ x0 = x2 ⊦ 〈if x0 ≠ [] then to := fail〉 to = fail

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Proof step 4:
x = [], x2 = x ∧ d0 = 0, to = fail ∧ x0 = x2 ⊦ 〈skip〉 to = fail

Rule argument

[fmapos-arg: pos: right 1]

Additional information

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