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Proof step 9 from proof booleanarray-put (previous step)

is_boolvalue(val), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval ⊦ (booleanvalues(getarray(r, 0, st[r -- _length] .intval, st))[i→n(i), val .boolval]) = booleanvalues(getarray(r, 0, st[r -- _length] .intval, st[r -- i ', val]))

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
val = boolval(boolvar), is_boolvalue(val), i < st[r -- _length] .intval, 0 ≤ i, 0 < st[r -- _length] .intval ⊦ (booleanvalues(getarray(r, 0, st[r -- _length] .intval, st))[i→n(i), boolvar]) = booleanvalues(getarray(r, 0, st[r -- _length] .intval, st[r -- i ', val]))

Rule argument

[x0lemmaarg: spec-name: javavalue instance-name: lemma-name: elim-08 antecedent: succedent: is_boolvalue(val) → ((boolvar ↔ val .boolval) ↔ val = boolval(boolvar)) substlist: [val, boolvar] → [val, boolvar] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_boolvalue(val) → ( (boolvar ↔ val .boolval) ↔ val = boolval(boolvar))])], [EXTRATERMS : (val, boolvar)]]