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Proof step 4 from proof boolvals-get (
previous step
)
m < # vals0, ∀ n. n < # vals0 → (booleanvalues(vals0)[n] ↔ vals0[n] .boolval) ⊦ booleanvalues(vals0)[m] ↔ vals0[m] .boolval, vals0 = []
User applied rule all left
And closed the goal!
Rule argument
[EXRARG : pos: left 2, [extquanttermlist: (m)abort:F, discard:F, computed:T]]
Additional information
[[CONCRETESIMPRULES : ()], [EXTRATERMS : (m)]]