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Proof step 29 from proof RED-complete (previous step)

∀ n0, t', t. n0 < m + 1 → (irred(t') ∧ (=> ^ n0)(t, t') → 〈RED(t; t0)〉 t0 = t'), irred(t'), t => t0, (=> ^ m)(t0, t'), tn0 = none ⊦ 〈RED1(t; tn0)〉〈if tn0 ≠ none then RED(tn0 .t; t1) else t1 := t〉 t1 = t'

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
∀ n0, t', t. n0 < m + 1 → (irred(t') ∧ (=> ^ n0)(t, t') → 〈RED(t; t0)〉 t0 = t'), irred(t'), t => t0, (=> ^ m)(t0, t') ⊦ 〈RED1(t; tn0)〉〈if tn0 ≠ none then RED(tn0 .t; t1) else t1 := t〉 t1 = t'

Rule argument

[emptyarg]

Additional information

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