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Proof step 5 from proof RED-complete (previous step)

〈RED1(t'; tn)〉 tn = tn1, ∀ n0, t', t. n0 < 0 → (irred(t') ∧ (=> ^ n0)(t, t') → 〈RED(t; t0)〉 t0 = t'), irred(t'), tn1 = none ⊃ irred(t') ; t' => tn1 .t, tn1 ≠ none ⊦ 〈RED(tn1 .t; t1)〉 t1 = t'

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ irred(t) → ¬ t => t0])]]