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Proof step 10 from proof RED-correct (previous step)

〈RED(t3; t0): kappa0 〉 t0 = t1, 〈RED1(t; tn0): kappa0 〉 tn0 = some(t3), 〈RED1(t; tn0)〉 tn0 = some(t3), irred(t1), (=> ^ n)(t3, t1), t => t3, ∀ t0. ¬ (t => t0 ∧ (=> ^ n)(t0, t1)) ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 7, [QUANTTERMLIST : (t3)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (t3)]]