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Proof step 31 from proof RED1-lem (previous step)

〈TOPRED(t; tn)〉 tn = tn1, ∀ t0. #(t0) < #(t) → (true → 〈RED1(t0; tn)〉 (tn = none ⊃ irred(t0); t0 => tn .t)), tn1 = none, ∀ t0. ¬ t =>top t0, ¬ ap(t), tn1 = none ⊃ ¬ irred(t) ; ¬ t => tn1 .t ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ ap(t) → (¬ irred(t) ↔ false)])]]