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Proof step 2 from proof kappa-RED1 (previous step)

〈abort〉 tn2 = tn1, 〈RED1(t; tn)〉 tn = tn0, ∀ n0, t, tn1, tn0. n0 < n → (〈RED1(t; tn): n0 〉 tn = tn1 ∧ 〈RED1(t; tn)〉 tn = tn0 ∧ tn0 ≠ tn1 → false), tn0 ≠ tn1, tn2 = tn, n = 0 ⊦

Heuristic symbolic execution applied rule abort left

And closed the goal!

Rule argument

[emptyarg]

Additional information

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