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Proof step 290 from proof kappa-RED1 (previous step)

〈tn1 := none〉 tn1 = tn0, ∀ n0, t, tn1, tn0. n0 < m + 1 → (〈RED1(t; tn3): n0 〉 tn3 = tn1 ∧ 〈RED1(t; tn3)〉 tn3 = tn0 ∧ tn0 ≠ tn1 → false), tn0 ≠ none, m ≠ 0, ¬ ap(t) ⊦

Heuristic symbolic execution applied rule assign left

And closed the goal!

Rule argument

[emptyarg]

Additional information

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