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Proof step 16 from proof kappa-TOPRED (previous step)

〈let v1 = (S _ t4 _ t3 _ t1) .1 .1 .2, v2 = (S _ t4 _ t3 _ t1) .1 .2, v3 = (S _ t4 _ t3 _ t1) .2 in if value(v1) ∧ value(v2) ∧ value(v3) then tn := some(v1 _ v3 _ (v2 _ v3)) else tn := none〉 tn = tn0, tn0 ≠ some(t4 _ t1 _ (t3 _ t1)), n ≠ 0, value(t4), value(t3), value(t1) ⊦

Heuristic symbolic execution applied rule vardecls left

And obtained the following new goals

Proof step 15:
〈if value(v4) ∧ value(v0) ∧ value(v) then tn := some(v4 _ v _ (v0 _ v)) else tn := none〉 tn = tn0, tn0 ≠ some(t4 _ t1 _ (t3 _ t1)), n ≠ 0, value(t4), value(t3), value(t1), v = (S _ t4 _ t3 _ t1) .2, v0 = (S _ t4 _ t3 _ t1) .1 .2, v4 = (S _ t4 _ t3 _ t1) .1 .1 .2 ⊦

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]