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Proof step 23 from proof kappa-TOPRED (previous step)

〈TOPRED(t0 _ t1; tn2)〉 tn2 = tn0, t0 .1 .1 = S, tn0 ≠ some(t0 .1 .2 _ t1 _ (t0 .2 _ t1)), n ≠ 0, t0 .1 ≠ K, ap(t0), ap(t0 .1), value(t0 .1 .2), value(t0 .2), value(t1) ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 22:
〈TOPRED(t0 _ t1; tn2)〉 tn2 = tn0, t2 .1 = S, tn0 ≠ some(t2 .2 _ t1 _ (t3 _ t1)), n ≠ 0, t2 ≠ K, ap(t0), ap(t2), value(t2 .2), value(t3), value(t1), t0 = t2 _ t3 ⊦

Rule argument

[x0lemmaarg: spec-name: term instance-name: lemma-name: elim antecedent: succedent: ap(t) → (t0 = t .1 ∧ t1 = t .2 ↔ t = t0 _ t1) substlist: [t, t0, t1] → [t0, t, t2] add preconditions?: F is rewrite lemma?: F current spec?: F rotate lemma?: T replace all?: T paths: () dummy: () ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ ap(t) → ( t0 = t .1 ∧ t1 = t .2 ↔ t = t0 _ t1)])], [EXTRATERMS : (t0, t, t2)]]