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Proof step 16 from proof ks-RED (previous step)

∀ n0. n0 < 1 → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), t1 = S, ks(1) .1 .1 ≠ K, value(ks(1) .2), value(ks(1) .1 .2), value(t2), ap(ks(1) .1 .1), ap(ks(1) .1), ap(ks(1)), ks(1) .1 .1 = t1 _ t2 ⊦ 〈RED(t2 _ ks(1) .2 _ (ks(1) .1 .2 _ ks(1) .2); t0)〉 t0 = K _ K

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
∀ n0. n0 < 1 → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), ks(1) .1 .1 = S _ t2, ap(ks(1)), ap(ks(1) .1), value(t2), value(ks(1) .1 .2), value(ks(1) .2) ⊦ 〈RED(t2 _ ks(1) .2 _ (ks(1) .1 .2 _ ks(1) .2); t0)〉 t0 = K _ K

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ap(t _ t0)], [CSIMPSEQ : ⊦ t _ t0 ≠ K])]]