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Proof step 48 from proof ks-RED (previous step)

∀ n0. n0 < 1 → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), tn1 = none ⊦ 〈n0 := 1〉〈tn := tn1 ; if tn ≠ none then tn := some(ks(n0) .1 _ tn .t)〉〈if tn ≠ none then RED(tn .t; t0) else t0 := ks(n0)〉 ((even(n0) → t0 = K) ∧ (odd(n0) → t0 = K _ K))

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 47:
∀ n0. n0 < 1 → (true → 〈RED(ks(n0); t)〉 ((even(n0) → t = K) ∧ (odd(n0) → t = K _ K))), tn1 = none, n = 1 ⊦ 〈tn := tn1〉〈if tn ≠ none then tn := some(ks(n) .1 _ tn .t)〉〈if tn ≠ none then RED(tn .t; t0) else t0 := ks(n)〉 ((even(n) → t0 = K) ∧ (odd(n) → t0 = K _ K))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]